What is the answer to |(x+2)(x-3)|=0 ?

The answer to |(x+2)(x-3)|=0 is x=-2\lor x=3

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|(x+2)(x-3)|=0

∣ (x + 2) (x - 3) ∣ = 0

x = - 2 or x = 3

Solution steps

∣ (x + 2) (x - 3) ∣ = 0

Apply absolute rule: If

∣ u ∣ = 0

then

u = 0

(x + 2) (x - 3) = 0

(x + 2) (x - 3) = 0 : x = - 2, x = 3

x = - 2 or x = 3

∣ y - 2 ∣ = 7

∣ 2 x + 11 ∣ = 7

2 x^{2} - 5 x = 4 - x

\frac{b}{3} = 2

∣ 3 - x ∣ = 0

What is the answer to |(x+2)(x-3)|=0 ?
The answer to |(x+2)(x-3)|=0 is x=-2\lor x=3
Solve for x: |(x+2)(x-3)|=0
The solution is x=-2\lor x=3