What are the solutions to the equation 2x^2-2=4x ?

The solutions to the equation 2x^2-2=4x are x=1+sqrt(2),x=1-sqrt(2)

Find the zeros of 2x^2-2=4x

The zeros of 2x^2-2=4x are x=1+sqrt(2),x=1-sqrt(2)

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2 x^{2} - 2 = 4 x

x = 1 + 2, x = 1 - 2

Solution steps

2 x^{2} - 2 = 4 x

Move

4 x

to the left side

2 x^{2} - 2 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 2) = 42

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 4 2}{2 \cdot 2}

x = \frac{- ( - 4 ) + 4 2}{2 \cdot 2} : 1 + 2

x = \frac{- ( - 4 ) - 4 2}{2 \cdot 2} : 1 - 2

The solutions to the quadratic equation are:

x = 1 + 2, x = 1 - 2

(2 x + 3)^{3} (x - 2)^{2} \leq 0

7 x^{2} - 14 x + 2 = 0

9 + \frac{n}{4} = 15

a^{2} b - b^{3}

2 y (9 x^{3} y)

What are the solutions to the equation 2x^2-2=4x ?
The solutions to the equation 2x^2-2=4x are x=1+sqrt(2),x=1-sqrt(2)
Find the zeros of 2x^2-2=4x
The zeros of 2x^2-2=4x are x=1+sqrt(2),x=1-sqrt(2)