What are the solutions to the equation 4x^2+101=36x ?

The solutions to the equation 4x^2+101=36x are x= 9/2+sqrt(5)i,x= 9/2-sqrt(5)i

Find the zeros of 4x^2+101=36x

The zeros of 4x^2+101=36x are x= 9/2+sqrt(5)i,x= 9/2-sqrt(5)i

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4 x^{2} + 101 = 36 x

x = \frac{9}{2} + 5 i, x = \frac{9}{2} - 5 i

Solution steps

4 x^{2} + 101 = 36 x

Move

36 x

to the left side

4 x^{2} + 101 - 36 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 36 x + 101 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 4 \cdot 101}{2 \cdot 4}

Simplify

(- 36)^{2} - 4 \cdot 4 \cdot 101 : 85 i

x_{1, 2} = \frac{- ( - 36 ) \pm 8 5 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 8 5 i}{2 \cdot 4}, x_{2} = \frac{- ( - 36 ) - 8 5 i}{2 \cdot 4}

x = \frac{- ( - 36 ) + 8 5 i}{2 \cdot 4} : \frac{9}{2} + 5 i

x = \frac{- ( - 36 ) - 8 5 i}{2 \cdot 4} : \frac{9}{2} - 5 i

The solutions to the quadratic equation are:

x = \frac{9}{2} + 5 i, x = \frac{9}{2} - 5 i

- 8 \leq 3 X + 1 \leq - 2

- x^{2} + 8 x - 7 = 0

- \frac{1}{3} + \frac{3}{8}

8 \geq y \geq 0

w^{3 x} + 8

What are the solutions to the equation 4x^2+101=36x ?
The solutions to the equation 4x^2+101=36x are x= 9/2+sqrt(5)i,x= 9/2-sqrt(5)i
Find the zeros of 4x^2+101=36x
The zeros of 4x^2+101=36x are x= 9/2+sqrt(5)i,x= 9/2-sqrt(5)i