What is the answer to |x^2-5|=1 ?

The answer to |x^2-5|=1 is x=-sqrt(6)\lor x=-2\lor x=2\lor x=sqrt(6)

Solve for x: |x^2-5|=1

The solution is x=-sqrt(6)\lor x=-2\lor x=2\lor x=sqrt(6)

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x^{2} - 5 = 1

x = - 6 or x = - 2 or x = 2 or x = 6

Decimal Notation

x = - 2.44948 \dots, x = - 2, x = 2, x = 2.44948 \dots

Solution steps

x^{2} - 5 = 1

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 5 = - 1 or x^{2} - 5 = 1

x^{2} - 5 = - 1 or x^{2} - 5 = 1

(x = - 2 or x = 2) or (x = - 6 or x = 6)

x = - 6 or x = - 2 or x = 2 or x = 6

∣ x + 5 ∣ - 1 = - 1

9 ∣ - 2 v + 1 ∣ + 1 = 46

x^{2} + 2 x - 5 = 3

- 2 ∣ 5 x - 7 ∣ + 9 = - 7

∣ 4 x + 2 ∣ = 5 x - 1

What is the answer to |x^2-5|=1 ?
The answer to |x^2-5|=1 is x=-sqrt(6)\lor x=-2\lor x=2\lor x=sqrt(6)
Solve for x: |x^2-5|=1
The solution is x=-sqrt(6)\lor x=-2\lor x=2\lor x=sqrt(6)