What are the solutions to the equation k^2+9k+20=0 ?

The solutions to the equation k^2+9k+20=0 are k=-4,k=-5

Find the zeros of k^2+9k+20=0

The zeros of k^2+9k+20=0 are k=-4,k=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

k^{2} + 9 k + 20 = 0

k = - 4, k = - 5

Solution steps

k^{2} + 9 k + 20 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

k_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 9 + 1}{2 \cdot 1}, k_{2} = \frac{- 9 - 1}{2 \cdot 1}

k = \frac{- 9 + 1}{2 \cdot 1} : - 4

k = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

k = - 4, k = - 5

5 x^{2} + 4 x - 2 = 0

- 5 ∣ 5 x - 6 ∣ - 4 = - 49

\frac{4 ^{3}}{4 ^{3}}

x 3 + 27 = 108

- 6 x - 8.4 = - 5 x - 15.4

What are the solutions to the equation k^2+9k+20=0 ?
The solutions to the equation k^2+9k+20=0 are k=-4,k=-5
Find the zeros of k^2+9k+20=0
The zeros of k^2+9k+20=0 are k=-4,k=-5