What are the solutions to the equation 5x^2+4x-2=0 ?

The solutions to the equation 5x^2+4x-2=0 are x=(-2+sqrt(14))/5 ,x=-(2+sqrt(14))/5

Find the zeros of 5x^2+4x-2=0

The zeros of 5x^2+4x-2=0 are x=(-2+sqrt(14))/5 ,x=-(2+sqrt(14))/5

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5 x^{2} + 4 x - 2 = 0

x = \frac{- 2 + 14}{5}, x = - \frac{2 + 14}{5}

Decimal Notation

x = 0.34833 \dots, x = - 1.14833 \dots

Solution steps

5 x^{2} + 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

4^{2} - 4 \cdot 5 (- 2) = 214

x_{1, 2} = \frac{- 4 \pm 2 14}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 4 + 2 14}{2 \cdot 5}, x_{2} = \frac{- 4 - 2 14}{2 \cdot 5}

x = \frac{- 4 + 2 14}{2 \cdot 5} : \frac{- 2 + 14}{5}

x = \frac{- 4 - 2 14}{2 \cdot 5} : - \frac{2 + 14}{5}

The solutions to the quadratic equation are:

x = \frac{- 2 + 14}{5}, x = - \frac{2 + 14}{5}

- 5 ∣ 5 x - 6 ∣ - 4 = - 49

\frac{4 ^{3}}{4 ^{3}}

x 3 + 27 = 108

- 6 x - 8.4 = - 5 x - 15.4

- 4 x + 10 = 30

What are the solutions to the equation 5x^2+4x-2=0 ?
The solutions to the equation 5x^2+4x-2=0 are x=(-2+sqrt(14))/5 ,x=-(2+sqrt(14))/5
Find the zeros of 5x^2+4x-2=0
The zeros of 5x^2+4x-2=0 are x=(-2+sqrt(14))/5 ,x=-(2+sqrt(14))/5