What are the solutions to the equation r^2+8r+25=0 ?

The solutions to the equation r^2+8r+25=0 are r=-4+3i,r=-4-3i

Find the zeros of r^2+8r+25=0

The zeros of r^2+8r+25=0 are r=-4+3i,r=-4-3i

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r^{2} + 8 r + 25 = 0

r = - 4 + 3 i, r = - 4 - 3 i

Solution steps

r^{2} + 8 r + 25 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 25 : 6 i

r_{1, 2} = \frac{- 8 \pm 6 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 8 + 6 i}{2 \cdot 1}, r_{2} = \frac{- 8 - 6 i}{2 \cdot 1}

r = \frac{- 8 + 6 i}{2 \cdot 1} : - 4 + 3 i

r = \frac{- 8 - 6 i}{2 \cdot 1} : - 4 - 3 i

The solutions to the quadratic equation are:

r = - 4 + 3 i, r = - 4 - 3 i

(b + 1)^{2} + (b + 1)

- x^{2} - 18 x - 54 = 0

318 - 22

∣ 2 x - 2 ∣ < 8

x + \frac{x + 5}{8} = \frac{x + 5}{16}

What are the solutions to the equation r^2+8r+25=0 ?
The solutions to the equation r^2+8r+25=0 are r=-4+3i,r=-4-3i
Find the zeros of r^2+8r+25=0
The zeros of r^2+8r+25=0 are r=-4+3i,r=-4-3i