What are the solutions to the equation r^2-4r+20=0 ?

The solutions to the equation r^2-4r+20=0 are r=2+4i,r=2-4i

Find the zeros of r^2-4r+20=0

The zeros of r^2-4r+20=0 are r=2+4i,r=2-4i

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r^{2} - 4 r + 20 = 0

r = 2 + 4 i, r = 2 - 4 i

Solution steps

r^{2} - 4 r + 20 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 20 : 8 i

r_{1, 2} = \frac{- ( - 4 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 4 ) + 8 i}{2 \cdot 1}, r_{2} = \frac{- ( - 4 ) - 8 i}{2 \cdot 1}

r = \frac{- ( - 4 ) + 8 i}{2 \cdot 1} : 2 + 4 i

r = \frac{- ( - 4 ) - 8 i}{2 \cdot 1} : 2 - 4 i

The solutions to the quadratic equation are:

r = 2 + 4 i, r = 2 - 4 i

\frac{1}{7} \cdot 2

81 x^{9} - 256 y^{8} x

w - \frac{1}{2} < - \frac{5}{8}

\frac{3}{2} x + 2 x = \frac{1}{2} x + 3

\frac{3 + \frac{18}{m}}{1 - \frac{36}{m ^{2}}}

What are the solutions to the equation r^2-4r+20=0 ?
The solutions to the equation r^2-4r+20=0 are r=2+4i,r=2-4i
Find the zeros of r^2-4r+20=0
The zeros of r^2-4r+20=0 are r=2+4i,r=2-4i