What is the answer to |x^2-5x+4|=0 ?

The answer to |x^2-5x+4|=0 is x=1\lor x=4

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|x^2-5x+4|=0

x^{2} - 5 x + 4 = 0

x = 1 or x = 4

Solution steps

x^{2} - 5 x + 4 = 0

Apply absolute rule: If

∣ u ∣ = 0

then

u = 0

x^{2} - 5 x + 4 = 0

x^{2} - 5 x + 4 = 0 : x = 4, x = 1

x = 1 or x = 4

∣ d + 8 ∣ - 10 = - 9

x^{2} - 1 = ∣ x ∣

x^{2} = ∣ 5 x + 6 ∣

\frac{3}{2} x - 6 = 6

4 ∣ 3 x - 4 ∣ = 32