What are the solutions to the equation 6x^2+2x-3=0 ?

The solutions to the equation 6x^2+2x-3=0 are x=(-1+sqrt(19))/6 ,x=-(1+sqrt(19))/6

Find the zeros of 6x^2+2x-3=0

The zeros of 6x^2+2x-3=0 are x=(-1+sqrt(19))/6 ,x=-(1+sqrt(19))/6

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6 x^{2} + 2 x - 3 = 0

x = \frac{- 1 + 19}{6}, x = - \frac{1 + 19}{6}

Decimal Notation

x = 0.55981 \dots, x = - 0.89314 \dots

Solution steps

6 x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

2^{2} - 4 \cdot 6 (- 3) = 219

x_{1, 2} = \frac{- 2 \pm 2 19}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 2 + 2 19}{2 \cdot 6}, x_{2} = \frac{- 2 - 2 19}{2 \cdot 6}

x = \frac{- 2 + 2 19}{2 \cdot 6} : \frac{- 1 + 19}{6}

x = \frac{- 2 - 2 19}{2 \cdot 6} : - \frac{1 + 19}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 19}{6}, x = - \frac{1 + 19}{6}

(x + 8)^{2} = 0

x^{2} + 14 x + 48

x - 12 = 3

3 x^{2} + 17 x - 20 = 0

\frac{4}{4} 5

What are the solutions to the equation 6x^2+2x-3=0 ?
The solutions to the equation 6x^2+2x-3=0 are x=(-1+sqrt(19))/6 ,x=-(1+sqrt(19))/6
Find the zeros of 6x^2+2x-3=0
The zeros of 6x^2+2x-3=0 are x=(-1+sqrt(19))/6 ,x=-(1+sqrt(19))/6