What is the answer to |2x+2|^2=5 ?

The answer to |2x+2|^2=5 is x=(-sqrt(5)-2)/2 \lor x=(sqrt(5)-2)/2

Solve for x: |2x+2|^2=5

The solution is x=(-sqrt(5)-2)/2 \lor x=(sqrt(5)-2)/2

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∣ 2 x + 2 ∣^{2} = 5

x = \frac{- 5 - 2}{2} or x = \frac{5 - 2}{2}

Decimal Notation

x = - 2.11803 \dots, x = 0.11803 \dots

Solution steps

∣ 2 x + 2 ∣^{2} = 5

Find positive and negative intervals

x < - 1, x \geq - 1

Solve the inequality for each interval

x = \frac{- 5 - 2}{2} or x = \frac{5 - 2}{2}

2 x^{2} - 3 - x = 3

∣ x - 8 ∣ = 16

y, x + ∣ y ∣ = 2 y

∣ - 4 - 3 n ∣ 4 = 2

∣ 6 x + 5 ∣ = 3

What is the answer to |2x+2|^2=5 ?
The answer to |2x+2|^2=5 is x=(-sqrt(5)-2)/2 \lor x=(sqrt(5)-2)/2
Solve for x: |2x+2|^2=5
The solution is x=(-sqrt(5)-2)/2 \lor x=(sqrt(5)-2)/2