What are the solutions to the equation 4x^2+9x+4=0 ?

The solutions to the equation 4x^2+9x+4=0 are x=(-9+sqrt(17))/8 ,x=(-9-sqrt(17))/8

Find the zeros of 4x^2+9x+4=0

The zeros of 4x^2+9x+4=0 are x=(-9+sqrt(17))/8 ,x=(-9-sqrt(17))/8

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4 x^{2} + 9 x + 4 = 0

x = \frac{- 9 + 17}{8}, x = \frac{- 9 - 17}{8}

Solution steps

4 x^{2} + 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

9^{2} - 4 \cdot 4 \cdot 4 = 17

x_{1, 2} = \frac{- 9 \pm 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 9 + 17}{2 \cdot 4}, x_{2} = \frac{- 9 - 17}{2 \cdot 4}

x = \frac{- 9 + 17}{2 \cdot 4} : \frac{- 9 + 17}{8}

x = \frac{- 9 - 17}{2 \cdot 4} : \frac{- 9 - 17}{8}

The solutions to the quadratic equation are:

x = \frac{- 9 + 17}{8}, x = \frac{- 9 - 17}{8}

(4 + i)^{2}

2 x + 5 + 2 x + 3 x = 2 x + 6

17 x - 16 \leq 52

\frac{3}{4} - 1

6 x^{2} - 11 x - 3 = 0

What are the solutions to the equation 4x^2+9x+4=0 ?
The solutions to the equation 4x^2+9x+4=0 are x=(-9+sqrt(17))/8 ,x=(-9-sqrt(17))/8
Find the zeros of 4x^2+9x+4=0
The zeros of 4x^2+9x+4=0 are x=(-9+sqrt(17))/8 ,x=(-9-sqrt(17))/8