What is the answer to |2x^2-9x-5|=0 ?

The answer to |2x^2-9x-5|=0 is x=-1/2 \lor x=5

Solve for x: |2x^2-9x-5|=0

The solution is x=-1/2 \lor x=5

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2 x^{2} - 9 x - 5 = 0

x = - \frac{1}{2} or x = 5

Decimal Notation

x = - 0.5, x = 5

Solution steps

2 x^{2} - 9 x - 5 = 0

Apply absolute rule: If

∣ u ∣ = 0

then

u = 0

2 x^{2} - 9 x - 5 = 0

2 x^{2} - 9 x - 5 = 0 : x = 5, x = - \frac{1}{2}

x = - \frac{1}{2} or x = 5

∣ v ∣ + 13 = 21

∣ 4 - 5 x ∣ = 4

- 10 + 5 ∣ 9 - 4 x ∣ = 115

∣ 0.2 x + 5 ∣ = x^{2} - 2

3 ∣ 3 (x + 5) (x - 1) ∣ + 5 = 32

What is the answer to |2x^2-9x-5|=0 ?
The answer to |2x^2-9x-5|=0 is x=-1/2 \lor x=5
Solve for x: |2x^2-9x-5|=0
The solution is x=-1/2 \lor x=5