What are the solutions to the equation 4x^2+8=20 ?

The solutions to the equation 4x^2+8=20 are x=sqrt(3),x=-sqrt(3)

Find the zeros of 4x^2+8=20

The zeros of 4x^2+8=20 are x=sqrt(3),x=-sqrt(3)

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4 x^{2} + 8 = 20

x = 3, x = - 3

Solution steps

4 x^{2} + 8 = 20

Move

8

to the right side

4 x^{2} = 12

Divide both sides by

4

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

3 x^{2} - x

x^{2} + 0.2 \cdot (1 - x) = 0

\frac{3}{8 x ^{3} y ^{3}} - \frac{1}{4 x y}

300 x > 160.5 x + 69750

\frac{7 ^{7}}{7 ^{5}}

What are the solutions to the equation 4x^2+8=20 ?
The solutions to the equation 4x^2+8=20 are x=sqrt(3),x=-sqrt(3)
Find the zeros of 4x^2+8=20
The zeros of 4x^2+8=20 are x=sqrt(3),x=-sqrt(3)