What are the solutions to the equation x^2-9x-1=0 ?

The solutions to the equation x^2-9x-1=0 are x=(9+sqrt(85))/2 ,x=(9-sqrt(85))/2

Find the zeros of x^2-9x-1=0

The zeros of x^2-9x-1=0 are x=(9+sqrt(85))/2 ,x=(9-sqrt(85))/2

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x^{2} - 9 x - 1 = 0

x = \frac{9 + 85}{2}, x = \frac{9 - 85}{2}

Decimal Notation

x = 9.10977 \dots, x = - 0.10977 \dots

Solution steps

x^{2} - 9 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 1) = 85

x_{1, 2} = \frac{- ( - 9 ) \pm 85}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 85}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 85}{2 \cdot 1}

x = \frac{- ( - 9 ) + 85}{2 \cdot 1} : \frac{9 + 85}{2}

x = \frac{- ( - 9 ) - 85}{2 \cdot 1} : \frac{9 - 85}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 85}{2}, x = \frac{9 - 85}{2}

12.5 x + 30.5 < 120

91 n^{2} + 201 mn + 108 m^{2}

x^{2} + 2 x + 16 = 0

\frac{3}{4} - \frac{5}{8} + \frac{7}{12}

\frac{5 x - 4}{2 x + 1} > 1

What are the solutions to the equation x^2-9x-1=0 ?
The solutions to the equation x^2-9x-1=0 are x=(9+sqrt(85))/2 ,x=(9-sqrt(85))/2
Find the zeros of x^2-9x-1=0
The zeros of x^2-9x-1=0 are x=(9+sqrt(85))/2 ,x=(9-sqrt(85))/2