What is (4y^2z^3-8yz^2)/(yz^2-2z) ?

The solution to (4y^2z^3-8yz^2)/(yz^2-2z) is 4yz

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (4y^2z^3-8yz^2)/(yz^2-2z)

simplify

\frac{4 y ^{2} z ^{3} - 8 y z ^{2}}{y z ^{2} - 2 z}

4 yz

Solution steps

\frac{4 y ^{2} z ^{3} - 8 y z ^{2}}{y z ^{2} - 2 z}

Factor

4 y^{2} z^{3} - 8 y z^{2} : 4 y z^{2} (yz - 2)

= \frac{4 y z ^{2} ( yz - 2 )}{y z ^{2} - 2 z}

Factor

y z^{2} - 2 z : z (yz - 2)

= \frac{4 y z ^{2} ( yz - 2 )}{z ( yz - 2 )}

Cancel the common factor:

yz - 2

= \frac{4 y z ^{2}}{z}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

z^{2} = zz

= \frac{4 yzz}{z}

Cancel the common factor:

z

= 4 yz

\frac{6 2}{3}

\frac{- 2 - 3 i}{4 + 5 i}

\frac{x + 3}{2} = x - 2

5 x^{2} + 75 = 40 x

- 3 \leq 5 x - 7 < 8

What is (4y^2z^3-8yz^2)/(yz^2-2z) ?
The solution to (4y^2z^3-8yz^2)/(yz^2-2z) is 4yz