|v|<= 6

The solution to |v|<= 6 is -6<= v<= 6

Solution

∣ v ∣ \leq 6

- 6 \leq v \leq 6

Interval Notation

[- 6, 6]

Solution steps

∣ v ∣ \leq 6

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 6 \leq v \leq 6

\frac{4 x ^{2} + 4 x y + y ^{2}}{4 x ^{2} - y ^{2}}

5 (p - 7) - 2 (3 p - 4) = 3 p

n^{2} - 14 n + 40

\frac{3}{2 - 5}

\frac{x ^{- 3} y ^{0} \cdot ( x y ^{- 3} ) ^{2}}{2 x ^{0}}