What is sqrt(6x-12)-8<= 4 ?

The solution to sqrt(6x-12)-8<= 4 is 2<= x<= 26

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sqrt(6x-12)-8<= 4

6 x - 12 - 8 \leq 4

2 \leq x \leq 26

Interval Notation

[2, 26]

Solution steps

6 x - 12 - 8 \leq 4

Move

8

to the right side

6 x - 12 \leq 12

Square both sides

(6 x - 12)^{2} \leq 1 2^{2}

Simplify

6 x - 12 \leq 144

6 x - 12 \leq 144 : x \leq 26

x \leq 26

Find singularity points

Find non-negative values for radicals:

x \geq 2

Combine the intervals

x \leq 26 and x \geq 2

Merge Overlapping Intervals

2 \leq x \leq 26

2 m + 5 - 6 m = 25

(x + 6)^{2} + 10 (x + 6) + 21 = 0

x^{2} - 11 x > - 28

3 x + 2 - 4 x + 1 + 9 x = 6 x - 1

2 n u - 8 u + 3 n - 12