What is the answer to x^2=|x-1| ?

The answer to x^2=|x-1| is x=(-1-sqrt(5))/2 \lor x=(-1+sqrt(5))/2

Solve for x: x^2=|x-1|

The solution is x=(-1-sqrt(5))/2 \lor x=(-1+sqrt(5))/2

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x^{2} = ∣ x - 1 ∣

x = \frac{- 1 - 5}{2} or x = \frac{- 1 + 5}{2}

Decimal Notation

x = - 1.61803 \dots, x = 0.61803 \dots

Solution steps

x^{2} = ∣ x - 1 ∣

Find positive and negative intervals

x < 1, x \geq 1

Solve the inequality for each interval

(x = \frac{- 1 - 5}{2} or x = \frac{- 1 + 5}{2}) or No Solution

x = \frac{- 1 - 5}{2} or x = \frac{- 1 + 5}{2}

∣ 9 x + 1 ∣ = 1

∣ 2 x + (- 1) ∣ = 5

∣ - 10 + n ∣ - 2 = - 8

∣ 8 x - 2 ∣ = 2

4 x^{2} + 8 x + 3 = 1

What is the answer to x^2=|x-1| ?
The answer to x^2=|x-1| is x=(-1-sqrt(5))/2 \lor x=(-1+sqrt(5))/2
Solve for x: x^2=|x-1|
The solution is x=(-1-sqrt(5))/2 \lor x=(-1+sqrt(5))/2