What are the solutions to the equation (x+3)(x+8)=x ?

The solutions to the equation (x+3)(x+8)=x are x=-4,x=-6

Find the zeros of (x+3)(x+8)=x

The zeros of (x+3)(x+8)=x are x=-4,x=-6

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(x + 3) (x + 8) = x

x = - 4, x = - 6

Solution steps

(x + 3) (x + 8) = x

Expand

(x + 3) (x + 8) : x^{2} + 11 x + 24

x^{2} + 11 x + 24 = x

Move

x

to the left side

x^{2} + 10 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

x_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2}{2 \cdot 1}, x_{2} = \frac{- 10 - 2}{2 \cdot 1}

x = \frac{- 10 + 2}{2 \cdot 1} : - 4

x = \frac{- 10 - 2}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 4, x = - 6

2^{14}

\frac{15 n}{30 n ^{3}}

22 5^{\frac{1}{2}}

8 = 7 + \frac{v}{6}

- 64 t^{2} = 1

What are the solutions to the equation (x+3)(x+8)=x ?
The solutions to the equation (x+3)(x+8)=x are x=-4,x=-6
Find the zeros of (x+3)(x+8)=x
The zeros of (x+3)(x+8)=x are x=-4,x=-6