What is the answer to ln(x^2-1)=3 ?

The answer to ln(x^2-1)=3 is x=sqrt(e^3+1),x=-sqrt(e^3+1)

Solve for x: ln(x^2-1)=3

The solution is x=sqrt(e^3+1),x=-sqrt(e^3+1)

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ln (x^{2} - 1) = 3

x = e^{3} + 1, x = - e^{3} + 1

Decimal Notation

x = 4.59189 \dots, x = - 4.59189 \dots

Solution steps

ln (x^{2} - 1) = 3

Apply log rules

x^{2} - 1 = e^{3}

Solve

x^{2} - 1 = e^{3} : x = e^{3} + 1, x = - e^{3} + 1

x = e^{3} + 1, x = - e^{3} + 1

lo g_{27} (a) = lo g_{3} (x)

lo g_{3} (x + 1) + lo g_{3} (x + 3) = 1

lo g_{10} (x) = 0

ln (x^{2}) + lo g_{7} (x) = 2

2 = - lo g_{10} (x)

What is the answer to ln(x^2-1)=3 ?
The answer to ln(x^2-1)=3 is x=sqrt(e^3+1),x=-sqrt(e^3+1)
Solve for x: ln(x^2-1)=3
The solution is x=sqrt(e^3+1),x=-sqrt(e^3+1)