What is the answer to ln((x+1)^2)=2 ?

The answer to ln((x+1)^2)=2 is x=e-1,x=-e-1

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ln((x+1)^2)=2

ln ((x + 1)^{2}) = 2

x = e - 1, x = - e - 1

Decimal Notation

x = 1.71828 \dots, x = - 3.71828 \dots

Solution steps

ln ((x + 1)^{2}) = 2

Apply log rules

(x + 1)^{2} = e^{2}

Solve

(x + 1)^{2} = e^{2} : x = e - 1, x = - e - 1

x = e - 1, x = - e - 1

lo g_{3} (x) = - 3

3 = - lo g_{10} (x)

ln (4 x) - 3 ln (x^{2}) = ln (2)

ln (x) - ln (x^{2}) = 5

lo g_{10} (x^{3} + 2000) = 2

What is the answer to ln((x+1)^2)=2 ?
The answer to ln((x+1)^2)=2 is x=e-1,x=-e-1
Solve for x: ln((x+1)^2)=2
The solution is x=e-1,x=-e-1