What is the answer to ln(sqrt(x+1))=2 ?

The answer to ln(sqrt(x+1))=2 is x=e^4-1

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ln(sqrt(x+1))=2

ln (x + 1) = 2

x = e^{4} - 1

Decimal Notation

x = 53.59815 \dots

Solution steps

ln (x + 1) = 2

Apply log rules

x + 1 = e^{2}

Solve

x + 1 = e^{2} : x = e^{4} - 1

x = e^{4} - 1

3 lo g_{2} (2 x + 7) = 9

lo g_{10} (x) + lo g_{10} (x - 15) = 2

lo g_{10} (3 x - 2) = 2

lo g_{8} (x) = \frac{1}{3}

2 lo g_{4} (x) - lo g_{4} (9) = 2

What is the answer to ln(sqrt(x+1))=2 ?
The answer to ln(sqrt(x+1))=2 is x=e^4-1
Solve for x: ln(sqrt(x+1))=2
The solution is x=e^4-1