What is the answer to 3log_{2}(2x+7)=9 ?

The answer to 3log_{2}(2x+7)=9 is x= 1/2

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3log_{2}(2x+7)=9

3 lo g_{2} (2 x + 7) = 9

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

3 lo g_{2} (2 x + 7) = 9

Divide both sides by

3

lo g_{2} (2 x + 7) = 3

Apply log rules

2 x + 7 = 8

Solve

2 x + 7 = 8 : x = \frac{1}{2}

x = \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

The solution is

x = \frac{1}{2}

lo g_{10} (x) + lo g_{10} (x - 15) = 2

lo g_{10} (3 x - 2) = 2

lo g_{8} (x) = \frac{1}{3}

2 lo g_{4} (x) - lo g_{4} (9) = 2

lo g_{10} (x - 1) = 2 + 2 lo g_{10} (x)

What is the answer to 3log_{2}(2x+7)=9 ?
The answer to 3log_{2}(2x+7)=9 is x= 1/2
Solve for x: 3log_{2}(2x+7)=9
The solution is x= 1/2