What is the answer to log_{10}(x-1)=2+2log_{10}(x) ?

The answer to log_{10}(x-1)=2+2log_{10}(x) is No Solution for x\in\mathbb{R}

Solve for x: log_{10}(x-1)=2+2log_{10}(x)

The solution is No Solution for x\in\mathbb{R}

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lo g_{10} (x - 1) = 2 + 2 lo g_{10} (x)

No Solution for x \in R

Solution steps

lo g_{10} (x - 1) = 2 + 2 lo g_{10} (x)

Apply log rules

x - 1 = 100 x^{2}

Solve

x - 1 = 100 x^{2} :

No Solution for

x \in R

No Solution for x \in R

lo g_{2} (x - 2) + lo g_{2} (x) = 3

- 6 lo g_{4} (5 x) = - 12

lo g_{2} (lo g_{10} (2 x - 1)) = 1

ln (x^{4}) - ln (x^{2}) = 2

lo g_{10} (x) + lo g_{10} (x + 15) = 2

What is the answer to log_{10}(x-1)=2+2log_{10}(x) ?
The answer to log_{10}(x-1)=2+2log_{10}(x) is No Solution for x\in\mathbb{R}
Solve for x: log_{10}(x-1)=2+2log_{10}(x)
The solution is No Solution for x\in\mathbb{R}