What is the answer to log_{4}(x)+log_{4}(x-6)=2 ?

The answer to log_{4}(x)+log_{4}(x-6)=2 is x=8

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log_{4}(x)+log_{4}(x-6)=2

lo g_{4} (x) + lo g_{4} (x - 6) = 2

x = 8

Solution steps

lo g_{4} (x) + lo g_{4} (x - 6) = 2

Apply log rules

x (x - 6) = 16

Solve

x (x - 6) = 16 : x = 8, x = - 2

x = 8, x = - 2

Verify Solutions:

x = 8

True

, x = - 2

False

The solution is

x = 8

ln (5 - 2 x) = - 3

ln (x^{2} - 1) = 0

ln (\frac{15}{13 - 2 x}) = ln (x)

lo g_{5} (x) = - 3

lo g_{2} (lo g_{3} (x)) = 2

What is the answer to log_{4}(x)+log_{4}(x-6)=2 ?
The answer to log_{4}(x)+log_{4}(x-6)=2 is x=8
Solve for x: log_{4}(x)+log_{4}(x-6)=2
The solution is x=8