What is the answer to ln(6)+ln(x)-ln(2)=3 ?

The answer to ln(6)+ln(x)-ln(2)=3 is x=(e^3)/3

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ln(6)+ln(x)-ln(2)=3

ln (6) + ln (x) - ln (2) = 3

x = \frac{e ^{3}}{3}

Decimal Notation

x = 6.69517 \dots

Solution steps

ln (6) + ln (x) - ln (2) = 3

Move

ln (6)

to the right side

ln (x) - ln (2) = 3 - ln (6)

Move

ln (2)

to the right side

ln (x) = 3 - ln (6) + ln (2)

Apply log rules

x = \frac{e ^{3}}{3}

Verify Solutions:

x = \frac{e ^{3}}{3}

True

The solution is

x = \frac{e ^{3}}{3}

lo g_{3} (4 x - 5) = lo g_{3} (2 x + 1)

lo g_{2} (x) - 3 = 1

lo g_{2} (x) = 1

ln (x - 3) = 2

lo g_{x} (5) = \frac{1}{2}

What is the answer to ln(6)+ln(x)-ln(2)=3 ?
The answer to ln(6)+ln(x)-ln(2)=3 is x=(e^3)/3
Solve for x: ln(6)+ln(x)-ln(2)=3
The solution is x=(e^3)/3