What is the answer to solvefor x,ln(2x-y-4)=0 ?

The answer to solvefor x,ln(2x-y-4)=0 is x=(y+5)/2

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solvefor x,ln(2x-y-4)=0

solve for

x, ln (2 x - y - 4) = 0

x = \frac{y + 5}{2}

Solution steps

ln (2 x - y - 4) = 0

Apply log rules

2 x - y - 4 = 1

Solve

2 x - y - 4 = 1 : x = \frac{y + 5}{2}

x = \frac{y + 5}{2}

ln (x - 5) + ln (x + 3) = 2 ln (3)

x, 3 ln (x^{4}) = 18

lo g_{x} (243) = 5

lo g_{3} (x - 5) = lo g_{3} (x) - 5

lo g_{2} (x - 1) + lo g_{2} (x + 3) = 1

What is the answer to solvefor x,ln(2x-y-4)=0 ?
The answer to solvefor x,ln(2x-y-4)=0 is x=(y+5)/2