What is the answer to log_{3}(x-5)=log_{3}(x)-5 ?

The answer to log_{3}(x-5)=log_{3}(x)-5 is x= 1215/242

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log_{3}(x-5)=log_{3}(x)-5

lo g_{3} (x - 5) = lo g_{3} (x) - 5

x = \frac{1215}{242}

Solution steps

lo g_{3} (x - 5) = lo g_{3} (x) - 5

Apply log rules

(x - 5) \cdot 243 = x

Solve

(x - 5) \cdot 243 = x : x = \frac{1215}{242}

x = \frac{1215}{242}

Verify Solutions:

x = \frac{1215}{242}

True

The solution is

x = \frac{1215}{242}

lo g_{2} (x - 1) + lo g_{2} (x + 3) = 1

lo g_{4} (2 - x) = lo g_{16} (13 - 4 x)

ln (x) = 10

lo g_{4} (x) = lo g_{4} (8 - x)

ln (3 x) + ln (x + 2) = 0

What is the answer to log_{3}(x-5)=log_{3}(x)-5 ?
The answer to log_{3}(x-5)=log_{3}(x)-5 is x= 1215/242
Solve for x: log_{3}(x-5)=log_{3}(x)-5
The solution is x= 1215/242