What is the answer to log_{4}(x)=log_{4}(8-x) ?

The answer to log_{4}(x)=log_{4}(8-x) is x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{4}(x)=log_{4}(8-x)

lo g_{4} (x) = lo g_{4} (8 - x)

x = 4

Solution steps

lo g_{4} (x) = lo g_{4} (8 - x)

Apply log rules

x = 8 - x

Solve

x = 8 - x : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

ln (3 x) + ln (x + 2) = 0

ln (x) + ln (x - 2) = ln (3)

lo g_{6} (x) = - 2

9 lo g_{x} (5) = lo g_{5} (x)

ln (x + 1) = 2

What is the answer to log_{4}(x)=log_{4}(8-x) ?
The answer to log_{4}(x)=log_{4}(8-x) is x=4
Solve for x: log_{4}(x)=log_{4}(8-x)
The solution is x=4