What is the answer to log_{2}(x)+log_{4}(x)=2 ?

The answer to log_{2}(x)+log_{4}(x)=2 is x=4^{2/3}

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log_{2}(x)+log_{4}(x)=2

lo g_{2} (x) + lo g_{4} (x) = 2

x = 4^{\frac{2}{3}}

Decimal Notation

x = 2.51984 \dots

Solution steps

lo g_{2} (x) + lo g_{4} (x) = 2

Apply log rules

x = 4^{\frac{2}{3}}

Verify Solutions:

x = 4^{\frac{2}{3}}

True

The solution is

x = 4^{\frac{2}{3}}

lo g_{2} (x + 3) + lo g_{2} (x - 3) = 4

lo g_{x} (81) = 2

lo g_{m} (32) = 5

lo g_{x} (81) = - 4

2 = ln (x)

What is the answer to log_{2}(x)+log_{4}(x)=2 ?
The answer to log_{2}(x)+log_{4}(x)=2 is x=4^{2/3}
Solve for x: log_{2}(x)+log_{4}(x)=2
The solution is x=4^{2/3}