What is the answer to 7=-log_{10}(x) ?

The answer to 7=-log_{10}(x) is x= 1/10000000

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7=-log_{10}(x)

7 = - lo g_{10} (x)

x = \frac{1}{10000000}

Solution steps

7 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

7 + lo g_{10} (x) = 0

Move

7

to the right side

lo g_{10} (x) = - 7

Apply log rules

x = \frac{1}{10000000}

Verify Solutions:

x = \frac{1}{10000000}

True

The solution is

x = \frac{1}{10000000}

ln (\frac{20}{7 - x}) = ln (2 x)

(ln (x))^{2} = ln (x^{2})

lo g_{x} (\frac{1}{9}) = 2

\frac{ln ( 3 x - 1 )}{ln ( x - 1 )} = 3

lo g_{10} (x) + lo g_{10} (x + 48) = 2

What is the answer to 7=-log_{10}(x) ?
The answer to 7=-log_{10}(x) is x= 1/10000000
Solve for x: 7=-log_{10}(x)
The solution is x= 1/10000000