What is the answer to log_{10}(x)+log_{10}(x+48)=2 ?

The answer to log_{10}(x)+log_{10}(x+48)=2 is x=2

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log_{10}(x)+log_{10}(x+48)=2

lo g_{10} (x) + lo g_{10} (x + 48) = 2

x = 2

Solution steps

lo g_{10} (x) + lo g_{10} (x + 48) = 2

Apply log rules

x (x + 48) = 100

Solve

x (x + 48) = 100 : x = 2, x = - 50

x = 2, x = - 50

Verify Solutions:

x = 2

True

, x = - 50

False

The solution is

x = 2

lo g_{10} (x) - lo g_{10} (x - 3) = 2

3 lo g_{2} (x) - 2 lo g_{2} (5 x) = 2

x, y = 4 \cdot ln (x + c)

2 = 2 x + ln (x)

lo g_{2} (x) - lo g_{4} (3 x + 4) = 0

What is the answer to log_{10}(x)+log_{10}(x+48)=2 ?
The answer to log_{10}(x)+log_{10}(x+48)=2 is x=2
Solve for x: log_{10}(x)+log_{10}(x+48)=2
The solution is x=2