What is the answer to solvefor x,y=4*ln(x+c) ?

The answer to solvefor x,y=4*ln(x+c) is x=e^{y/4}-c

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solvefor x,y=4*ln(x+c)

solve for

x, y = 4 \cdot ln (x + c)

x = e^{\frac{y}{4}} - c

Solution steps

y = 4 ln (x + c)

Switch sides

4 ln (x + c) = y

Divide both sides by

4

ln (x + c) = \frac{y}{4}

Apply log rules

x + c = e^{\frac{y}{4}}

Solve

x + c = e^{\frac{y}{4}} : x = e^{\frac{y}{4}} - c

x = e^{\frac{y}{4}} - c

2 = 2 x + ln (x)

lo g_{2} (x) - lo g_{4} (3 x + 4) = 0

ln (x) = ln (x)

lo g_{10} (x) = 0.66

ln (x) + ln (x - 5) = 0

What is the answer to solvefor x,y=4*ln(x+c) ?
The answer to solvefor x,y=4*ln(x+c) is x=e^{y/4}-c