What is the answer to log_{2}(x-1)+log_{2}(x+1)=3 ?

The answer to log_{2}(x-1)+log_{2}(x+1)=3 is x=3

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log_{2}(x-1)+log_{2}(x+1)=3

lo g_{2} (x - 1) + lo g_{2} (x + 1) = 3

x = 3

Solution steps

lo g_{2} (x - 1) + lo g_{2} (x + 1) = 3

Apply log rules

(x - 1) (x + 1) = 8

Solve

(x - 1) (x + 1) = 8 : x = 3, x = - 3

x = 3, x = - 3

Verify Solutions:

x = 3

True

, x = - 3

False

The solution is

x = 3

lo g_{x} (\frac{1}{8}) = 3

\frac{ln ( x )}{x} = 0

ln (7 - x) - ln (10) = ln (x)

lo g_{8} (x - 3) + lo g_{8} (x + 4) = 1

ln (x) = - \frac{1}{2}

What is the answer to log_{2}(x-1)+log_{2}(x+1)=3 ?
The answer to log_{2}(x-1)+log_{2}(x+1)=3 is x=3
Solve for x: log_{2}(x-1)+log_{2}(x+1)=3
The solution is x=3