What is the answer to log_{8}(x-3)+log_{8}(x+4)=1 ?

The answer to log_{8}(x-3)+log_{8}(x+4)=1 is x=4

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log_{8}(x-3)+log_{8}(x+4)=1

lo g_{8} (x - 3) + lo g_{8} (x + 4) = 1

x = 4

Solution steps

lo g_{8} (x - 3) + lo g_{8} (x + 4) = 1

Apply log rules

(x - 3) (x + 4) = 8

Solve

(x - 3) (x + 4) = 8 : x = 4, x = - 5

x = 4, x = - 5

Verify Solutions:

x = 4

True

, x = - 5

False

The solution is

x = 4

ln (x) = - \frac{1}{2}

ln (x) + ln (x + 1) = 1

ln (x - 2) + ln (x) = 1

lo g_{2} (x) + lo g_{2} (x + 1) = 1

lo g_{x} (125) = - 3

What is the answer to log_{8}(x-3)+log_{8}(x+4)=1 ?
The answer to log_{8}(x-3)+log_{8}(x+4)=1 is x=4
Solve for x: log_{8}(x-3)+log_{8}(x+4)=1
The solution is x=4