What is the answer to log_{2}(x)+log_{2}(x+1)=1 ?

The answer to log_{2}(x)+log_{2}(x+1)=1 is x=1

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log_{2}(x)+log_{2}(x+1)=1

lo g_{2} (x) + lo g_{2} (x + 1) = 1

x = 1

Solution steps

lo g_{2} (x) + lo g_{2} (x + 1) = 1

Apply log rules

x (x + 1) = 2

Solve

x (x + 1) = 2 : x = 1, x = - 2

x = 1, x = - 2

Verify Solutions:

x = 1

True

, x = - 2

False

The solution is

x = 1

lo g_{x} (125) = - 3

ln (x) + ln (x - 2) = 1

ln (x) + ln (x - 2) = 0

lo g_{\frac{3}{4}} (x) = 2

3 lo g_{9} (x) = (lo g_{3} (x))^{2}

What is the answer to log_{2}(x)+log_{2}(x+1)=1 ?
The answer to log_{2}(x)+log_{2}(x+1)=1 is x=1
Solve for x: log_{2}(x)+log_{2}(x+1)=1
The solution is x=1