What is the answer to ln(x)+ln(x-2)=1 ?

The answer to ln(x)+ln(x-2)=1 is x=(2+sqrt(4+4e))/2

Solve for x: ln(x)+ln(x-2)=1

The solution is x=(2+sqrt(4+4e))/2

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ln (x) + ln (x - 2) = 1

x = \frac{2 + 4 + 4 e}{2}

Decimal Notation

x = 2.92828 \dots

Solution steps

ln (x) + ln (x - 2) = 1

Apply log rules

x (x - 2) = e

Solve

x (x - 2) = e : x = \frac{2 + 4 + 4 e}{2}, x = \frac{2 - 4 + 4 e}{2}

x = \frac{2 + 4 + 4 e}{2}, x = \frac{2 - 4 + 4 e}{2}

Verify Solutions:

x = \frac{2 + 4 + 4 e}{2}

True

, x = \frac{2 - 4 + 4 e}{2}

False

The solution is

x = \frac{2 + 4 + 4 e}{2}

ln (x) + ln (x - 2) = 0

lo g_{\frac{3}{4}} (x) = 2

3 lo g_{9} (x) = (lo g_{3} (x))^{2}

lo g_{4} (x) + lo g_{4} (x + 6) = 2

ln (x^{2}) = 20

What is the answer to ln(x)+ln(x-2)=1 ?
The answer to ln(x)+ln(x-2)=1 is x=(2+sqrt(4+4e))/2
Solve for x: ln(x)+ln(x-2)=1
The solution is x=(2+sqrt(4+4e))/2