What is the answer to log_{10}(x)+log_{10}(x-5)=1 ?

The answer to log_{10}(x)+log_{10}(x-5)=1 is x=(5+sqrt(65))/2

Solve for x: log_{10}(x)+log_{10}(x-5)=1

The solution is x=(5+sqrt(65))/2

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lo g_{10} (x) + lo g_{10} (x - 5) = 1

x = \frac{5 + 65}{2}

Solution steps

lo g_{10} (x) + lo g_{10} (x - 5) = 1

Apply log rules

x (x - 5) = 10

Solve

x (x - 5) = 10 : x = \frac{5 + 65}{2}, x = \frac{5 - 65}{2}

x = \frac{5 + 65}{2}, x = \frac{5 - 65}{2}

Verify Solutions:

x = \frac{5 + 65}{2}

True

, x = \frac{5 - 65}{2}

False

The solution is

x = \frac{5 + 65}{2}

lo g_{2} (3 x - 2) = 4

7 lo g_{5} (x + 27) = 14

1 + lo g_{2} (- 5 x) = 4

ln (x + 1) = 0

ln (x + 1) - ln (x) = 2

What is the answer to log_{10}(x)+log_{10}(x-5)=1 ?
The answer to log_{10}(x)+log_{10}(x-5)=1 is x=(5+sqrt(65))/2
Solve for x: log_{10}(x)+log_{10}(x-5)=1
The solution is x=(5+sqrt(65))/2