What is the answer to ln(2)-ln(3x+2)=1 ?

The answer to ln(2)-ln(3x+2)=1 is x=(2-2e)/(3e)

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ln(2)-ln(3x+2)=1

ln (2) - ln (3 x + 2) = 1

x = \frac{2 - 2 e}{3 e}

Solution steps

ln (2) - ln (3 x + 2) = 1

Move

ln (2)

to the right side

- ln (3 x + 2) = 1 - ln (2)

Divide both sides by

- 1

ln (3 x + 2) = - 1 + ln (2)

Apply log rules

3 x + 2 = \frac{2}{e}

Solve

3 x + 2 = \frac{2}{e} : x = \frac{2 - 2 e}{3 e}

x = \frac{2 - 2 e}{3 e}

Verify Solutions:

x = \frac{2 - 2 e}{3 e}

True

The solution is

x = \frac{2 - 2 e}{3 e}

2 lo g_{4} (x) - lo g_{4} (x - 1) = 1

lo g_{x} (3) = \frac{1}{2}

1 = lo g_{10} (x)

0.4 = lo g_{10} (x)

lo g_{10} (x) + lo g_{10} (x + 3) = - 1

What is the answer to ln(2)-ln(3x+2)=1 ?
The answer to ln(2)-ln(3x+2)=1 is x=(2-2e)/(3e)
Solve for x: ln(2)-ln(3x+2)=1
The solution is x=(2-2e)/(3e)