What is the answer to log_{10}(x)+log_{10}(x+3)=-1 ?

The answer to log_{10}(x)+log_{10}(x+3)=-1 is x=(-15+sqrt(235))/(10)

Solve for x: log_{10}(x)+log_{10}(x+3)=-1

The solution is x=(-15+sqrt(235))/(10)

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lo g_{10} (x) + lo g_{10} (x + 3) = - 1

x = \frac{- 15 + 235}{10}

Solution steps

lo g_{10} (x) + lo g_{10} (x + 3) = - 1

Apply log rules

x (x + 3) = \frac{1}{10}

Solve

x (x + 3) = \frac{1}{10} : x = \frac{- 15 + 235}{10}, x = - \frac{15 + 235}{10}

x = \frac{- 15 + 235}{10}, x = - \frac{15 + 235}{10}

Verify Solutions:

x = \frac{- 15 + 235}{10}

True

, x = - \frac{15 + 235}{10}

False

The solution is

x = \frac{- 15 + 235}{10}

2 lo g_{3} (x) - lo g_{3} (7 x) = 1

- 5 lo g_{3} (2 x) = - 5

lo g_{10} (5 x) + lo g_{10} (x - 1) = 2

lo g_{10} (x) + lo g_{10} (x - 9) = 1

lo g_{2} (x^{2}) - lo g_{x} (x) = 7

What is the answer to log_{10}(x)+log_{10}(x+3)=-1 ?
The answer to log_{10}(x)+log_{10}(x+3)=-1 is x=(-15+sqrt(235))/(10)
Solve for x: log_{10}(x)+log_{10}(x+3)=-1
The solution is x=(-15+sqrt(235))/(10)