What is the answer to log_{10}(5x)+log_{10}(x-1)=2 ?

The answer to log_{10}(5x)+log_{10}(x-1)=2 is x=5

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log_{10}(5x)+log_{10}(x-1)=2

lo g_{10} (5 x) + lo g_{10} (x - 1) = 2

x = 5

Solution steps

lo g_{10} (5 x) + lo g_{10} (x - 1) = 2

Apply log rules

5 x (x - 1) = 100

Solve

5 x (x - 1) = 100 : x = 5, x = - 4

x = 5, x = - 4

Verify Solutions:

x = 5

True

, x = - 4

False

The solution is

x = 5

lo g_{10} (x) + lo g_{10} (x - 9) = 1

lo g_{2} (x^{2}) - lo g_{x} (x) = 7

2 lo g_{3} (x + 15) - lo g_{3} (x) = 4

lo g_{2} (x + 2) - lo g_{2} (x - 5) = 3

ln (x - 5) = 1

What is the answer to log_{10}(5x)+log_{10}(x-1)=2 ?
The answer to log_{10}(5x)+log_{10}(x-1)=2 is x=5
Solve for x: log_{10}(5x)+log_{10}(x-1)=2
The solution is x=5