What is the answer to 4+log_{3}(-2x)=5 ?

The answer to 4+log_{3}(-2x)=5 is x=-3/2

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4+log_{3}(-2x)=5

4 + lo g_{3} (- 2 x) = 5

x = - \frac{3}{2}

Solution steps

4 + lo g_{3} (- 2 x) = 5

Move

4

to the right side

lo g_{3} (- 2 x) = 1

Apply log rules

- 2 x = 3

Solve

- 2 x = 3 : x = - \frac{3}{2}

x = - \frac{3}{2}

Verify Solutions:

x = - \frac{3}{2}

True

The solution is

x = - \frac{3}{2}

lo g_{2} (x + 2) + lo g_{2} (x - 1) = 2

lo g_{10} (1 + x) = 3

lo g_{2} (x) = 8 + 9 lo g_{x} (2)

ln (3 x - 2) + ln (x - 1) = 2 ln (x)

lo g_{5} (x) = - 1

What is the answer to 4+log_{3}(-2x)=5 ?
The answer to 4+log_{3}(-2x)=5 is x=-3/2
Solve for x: 4+log_{3}(-2x)=5
The solution is x=-3/2