What is the answer to ln(x)+ln(x+2)=1 ?

The answer to ln(x)+ln(x+2)=1 is x=(-2+sqrt(4+4e))/2

Solve for x: ln(x)+ln(x+2)=1

The solution is x=(-2+sqrt(4+4e))/2

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ln (x) + ln (x + 2) = 1

x = \frac{- 2 + 4 + 4 e}{2}

Solution steps

ln (x) + ln (x + 2) = 1

Apply log rules

x (x + 2) = e

Solve

x (x + 2) = e : x = \frac{- 2 + 4 + 4 e}{2}, x = \frac{- 2 - 4 + 4 e}{2}

x = \frac{- 2 + 4 + 4 e}{2}, x = \frac{- 2 - 4 + 4 e}{2}

Verify Solutions:

x = \frac{- 2 + 4 + 4 e}{2}

True

, x = \frac{- 2 - 4 + 4 e}{2}

False

The solution is

x = \frac{- 2 + 4 + 4 e}{2}

ln (x) + \frac{1}{2} = ln (x)

lo g_{9} (x) = 2

1 = - lo g_{10} (x)

lo g_{2} (x - 6) = 2 - lo g_{2} (x - 3)

lo g_{10} (x) = 10

What is the answer to ln(x)+ln(x+2)=1 ?
The answer to ln(x)+ln(x+2)=1 is x=(-2+sqrt(4+4e))/2
Solve for x: ln(x)+ln(x+2)=1
The solution is x=(-2+sqrt(4+4e))/2