What is the answer to 1=-log_{10}(x) ?

The answer to 1=-log_{10}(x) is x= 1/10

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1=-log_{10}(x)

1 = - lo g_{10} (x)

x = \frac{1}{10}

Solution steps

1 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

1 + lo g_{10} (x) = 0

Move

1

to the right side

lo g_{10} (x) = - 1

Apply log rules

x = \frac{1}{10}

Verify Solutions:

x = \frac{1}{10}

True

The solution is

x = \frac{1}{10}

lo g_{2} (x - 6) = 2 - lo g_{2} (x - 3)

lo g_{10} (x) = 10

lo g_{a} (x^{2}) - 4 = 2 lo g_{a} (6)

lo g_{x} (9) = - 2

lo g_{2} (x) + lo g_{2} (x - 6) = 4