What is the answer to log_{2}(x)+log_{2}(x-6)=4 ?

The answer to log_{2}(x)+log_{2}(x-6)=4 is x=8

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log_{2}(x)+log_{2}(x-6)=4

lo g_{2} (x) + lo g_{2} (x - 6) = 4

x = 8

Solution steps

lo g_{2} (x) + lo g_{2} (x - 6) = 4

Apply log rules

x (x - 6) = 16

Solve

x (x - 6) = 16 : x = 8, x = - 2

x = 8, x = - 2

Verify Solutions:

x = 8

True

, x = - 2

False

The solution is

x = 8

ln (x^{2}) = 10

ln (x + 1) - ln (x) = 1

lo g_{2} (x + 2) = 3

lo g_{3} (2 x + 1) = 2 + lo g_{3} (x - 9)

5 lo g_{4} (x) - lo g_{4} (3) = 2

What is the answer to log_{2}(x)+log_{2}(x-6)=4 ?
The answer to log_{2}(x)+log_{2}(x-6)=4 is x=8
Solve for x: log_{2}(x)+log_{2}(x-6)=4
The solution is x=8