What is the answer to log_{3}(2x+1)=2+log_{3}(x-9) ?

The answer to log_{3}(2x+1)=2+log_{3}(x-9) is x= 82/7

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log_{3}(2x+1)=2+log_{3}(x-9)

lo g_{3} (2 x + 1) = 2 + lo g_{3} (x - 9)

x = \frac{82}{7}

Decimal Notation

x = 11.71428 \dots

Solution steps

lo g_{3} (2 x + 1) = 2 + lo g_{3} (x - 9)

Apply log rules

2 x + 1 = 9 (x - 9)

Solve

2 x + 1 = 9 (x - 9) : x = \frac{82}{7}

x = \frac{82}{7}

Verify Solutions:

x = \frac{82}{7}

True

The solution is

x = \frac{82}{7}

5 lo g_{4} (x) - lo g_{4} (3) = 2

lo g_{x - 1} (x + 5) = 2

lo g_{3} (2 - x) = 3

lo g_{x} (27) = \frac{3}{2}

ln (x^{2}) = (ln (x))^{2}

What is the answer to log_{3}(2x+1)=2+log_{3}(x-9) ?
The answer to log_{3}(2x+1)=2+log_{3}(x-9) is x= 82/7
Solve for x: log_{3}(2x+1)=2+log_{3}(x-9)
The solution is x= 82/7