What is the answer to log_{9}(x^2-10)=1 ?

The answer to log_{9}(x^2-10)=1 is x=sqrt(19),x=-sqrt(19)

Solve for x: log_{9}(x^2-10)=1

The solution is x=sqrt(19),x=-sqrt(19)

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lo g_{9} (x^{2} - 10) = 1

x = 19, x = - 19

Decimal Notation

x = 4.35889 \dots, x = - 4.35889 \dots

Solution steps

lo g_{9} (x^{2} - 10) = 1

Apply log rules

x^{2} - 10 = 9

Solve

x^{2} - 10 = 9 : x = 19, x = - 19

x = 19, x = - 19

ln^{2} (x) = 0

lo g_{5} (x) (lo g_{5} (x) - 3) = 10

lo g_{x} (16) = - 2

lo g_{4} (x - 3) = 1 - lo g_{4} (x)

lo g_{10} (7) + lo g_{10} (x - 4) = 1

What is the answer to log_{9}(x^2-10)=1 ?
The answer to log_{9}(x^2-10)=1 is x=sqrt(19),x=-sqrt(19)
Solve for x: log_{9}(x^2-10)=1
The solution is x=sqrt(19),x=-sqrt(19)