What is the answer to log_{3}(x-9)+log_{3}(x-3)=2 ?

The answer to log_{3}(x-9)+log_{3}(x-3)=2 is x=3(2+sqrt(2))

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log_{3}(x-9)+log_{3}(x-3)=2

lo g_{3} (x - 9) + lo g_{3} (x - 3) = 2

x = 3 (2 + 2)

Decimal Notation

x = 10.24264 \dots

Solution steps

lo g_{3} (x - 9) + lo g_{3} (x - 3) = 2

Apply log rules

(x - 9) (x - 3) = 9

Solve

(x - 9) (x - 3) = 9 : x = 3 (2 + 2), x = 3 (2 - 2)

x = 3 (2 + 2), x = 3 (2 - 2)

Verify Solutions:

x = 3 (2 + 2)

True

, x = 3 (2 - 2)

False

The solution is

x = 3 (2 + 2)

lo g_{5} (2 x + 1) = 2

x, ln (ln (x)) = 1

lo g_{2} (x - 5) = 1

lo g_{4} (x - 6) = 1 - lo g_{4} (x - 3)

ln (x + 1) + ln (x - 1) = 3

What is the answer to log_{3}(x-9)+log_{3}(x-3)=2 ?
The answer to log_{3}(x-9)+log_{3}(x-3)=2 is x=3(2+sqrt(2))
Solve for x: log_{3}(x-9)+log_{3}(x-3)=2
The solution is x=3(2+sqrt(2))