What is the answer to ln(x)+ln(x-7)=0 ?

The answer to ln(x)+ln(x-7)=0 is x=(7+sqrt(53))/2

Solve for x: ln(x)+ln(x-7)=0

The solution is x=(7+sqrt(53))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln (x) + ln (x - 7) = 0

x = \frac{7 + 53}{2}

Decimal Notation

x = 7.14005 \dots

Solution steps

ln (x) + ln (x - 7) = 0

Apply log rules

x (x - 7) = 1

Solve

x (x - 7) = 1 : x = \frac{7 + 53}{2}, x = \frac{7 - 53}{2}

x = \frac{7 + 53}{2}, x = \frac{7 - 53}{2}

Verify Solutions:

x = \frac{7 + 53}{2}

True

, x = \frac{7 - 53}{2}

False

The solution is

x = \frac{7 + 53}{2}

lo g_{3} (x) = 9

lo g_{x} (256) = 8

ln (x - 2) = 2 + 3 ln (2)

lo g_{2} (x + 3) = 3 - lo g_{2} (x + 5)

lo g_{4} (2 x + 4) - 3 = lo g_{4} (3)

What is the answer to ln(x)+ln(x-7)=0 ?
The answer to ln(x)+ln(x-7)=0 is x=(7+sqrt(53))/2
Solve for x: ln(x)+ln(x-7)=0
The solution is x=(7+sqrt(53))/2